Question

What is the volume of oxygen at stp required for the complete combustion of 4gram methane

Answer 1

1 mole of methane requires 2 moles of oxygen.
Here 4 gm methane (0.25 mole) requires 0.5 mole of oxygen.
Now, the volume of 1 mole of a gas at STP is 22.4 L and here half mole of oxygen will occupy 11.2 L.
answer → 11.2 L. :)

Answer 2

1 moles of methane requires 2 moles of oxygen here 4g methane (0.25 mole) requires 0.5 moles of oxygen now the volume of 1 moles of a gas at STP is 22.4L and here half mole of oxygen will occupy 11.2L .So, the answer is 11.2L