Question

What is the volume of S.T.P of 2.8 g of nitrogen gas . [N=14]

Answer 1

Answer:

Explanation:

One mole of nitrogen gas occupies 22.4 L of volume.

So let us first find out the number of moles.......

So N2 = 2*14 = 28 g/mol.

So 2.8 g of N2 contains

(2.8 / 28 )moles = 0.1 mole.

So the gas will occupy a volume of 0.1 * 22.4 = 2.24 L of volume.

PLEASE MARK BRAINIEST

Answer 2

Given:

Given: 2.8 grams of nitrogen gas.

To find:

We have to find the volume at S.T.P.

Solution:

To determine the volume of 2.8 grams of nitrogen gas at S.T.P we have to follow the below steps as follows-

The atomic weight of nitrogen is 14 grams.

Thus, the molecular weight of nitrogen gas is 14×2=28 grams.

Now at S.T.P 28 grams of nitrogen gas has a volume of 22.4 litres.

Thus 2.8 grams of nitrogen gas has a volume of 2.8×22.4/28=2.24 litres.

Thus 2.8 grams of nitrogen gas has a volume of 2.24 litres at S.T.P