What is the volume of the iron required to make a 70 centimetre long rod of 2.1 CM diameter?
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volume of cylinder=πr^2h. =22/7×2.1/2×2.1/2×70. =11×2.1×2.1×5. =55×4.41. =242.55cm^3
tarunvyas248:
its 242.55
Answered by
6
according to the question, the rod is of cylinder shape.
height of cylinder = 70 cm
radius of cylinder = diameter/2 = 2.1/2 = 21/20
volume of cylinder = volume of iron
volume of cylinder = pi x (radius)square x height of cylinder
volume of cylinder = 22/7 x 21/20 x 21/20 x 70
volume of cylinder = (11 x 21 x 21) / 20
volume of cylinder = 4851 / 20
volume of cylinder = 242.55 cubic cm.
Hence, the volume of iron is 242.55 cubic cm.
height of cylinder = 70 cm
radius of cylinder = diameter/2 = 2.1/2 = 21/20
volume of cylinder = volume of iron
volume of cylinder = pi x (radius)square x height of cylinder
volume of cylinder = 22/7 x 21/20 x 21/20 x 70
volume of cylinder = (11 x 21 x 21) / 20
volume of cylinder = 4851 / 20
volume of cylinder = 242.55 cubic cm.
Hence, the volume of iron is 242.55 cubic cm.
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