What is the volume of the solid consist of a right circular cone of height h and radius standing on a hemisphere of same radius?
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Volume of water left in cylinder
=
Volume of cylinder
−
Volume of solid
Volume of cylinder:
Radius,
r
=
60
c
m
Height,
h
=
180
c
m
Volume of outer cylinder =
π
r
2
h
=
22
7
×
60
2
×
180
=
14256000
7
Volume of solid
=
Volume of cone
+
Volume of hemisphere
Volume of cone:
Radius,
r
=
60
c
m
Height,
h
=
120
c
m
Volume of cone =
1
3
π
r
2
h
=
1
3
×
22
7
×
60
2
×
12
=
316800
7
c
m
3
Volume of hemisphere:
radius,
r
=
60
c
m
Volume =
2
3
π
r
3
=
2
3
×
22
7
×
60
3
=
3268000
7
Volume of solid
=
3268000
7
+
3268000
7
=
6336000
7
Now, Volume of water left in cylinder
=
Volume of cylinder - Volume of solid
=
14256000
7
−
6336000
7
=
7920000
7
c
m
3
=
1131428.57
c
m
3
=
1131428.57
×
1
100
×
1
100
×
1
100
m
3
[Since,
1
c
m
=
1
100
]
=
1.131
m
3
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