Question

What is the volume ratio of equal masses of hydrogen methane and oxygen present under ` similar conditions? `

Answer 1

Answer:

Let assume mass=x

No. of moles =n(O2)=32x

n(H2)=2x

n(CH4)=16x

Now ,divide every value by smallest value which is 32x

32x32x:32x2x:32x16x=O2:H2:CH4⇒1:16:2

Explanation:

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