Question

What is the VSEPR treatment of hydrazine?

Answer 1

There are 4×1+2×7=18⋅electrons to distribute around 6 centres........

Explanation:

And so for hydrazine, we write,

H2..N−..NH2; these represent 14 valence electrons, 4×N−H, and 1×N−N, and 2×N lone pairs.

The remaining 4 electrons are conceived to be the inner core electrons on the nitrogen centre (i.e. the original 1s2 sets). Anyway, we have distributed 18 electrons as required, 14 are valence electrons. 

I hope I help you

please don't forget to follow me