Question

What is the wavelength (Å) of a photon that has an energy of 4.38 x 10-18 J (1) 454 Å (2) 2.3 x 107 Å (3) 6.89 x 1015 Å (1) 454 (4) 1.45 x 10-15 Å​

Answer 1

The wavelength (Å) of a photon that has an energy of 4.38 x 10-18 J is

(1) 454 Å

Given: Energy of photon is 4.38 x 10-18 J

E = 4.38 x 10-18 J , c = 3 × 10^8 m/s, h = 6.626 × 10^-34 J.s

To Find: The wavelength (Å) of a photon

Solution:

The energy of a system is given by the formula,

E = hv                                   [ where h = Plancks constant , v = frequency]

v = c / λ                                 [ where c = velocity of light , λ= wavelength ]

∴ E = h×c/λ                                 ... ( 1 )

we know that E = 4.38 x 10-18 J , c = 3 × 10^8 m/s, h = 6.626 × 10^-34 J.s

Putting the above values in ( 1 ) we get,

λ = ( 6.626 × 10^-34 ×  3 × 10^8 ) / 4.38 x 10-18  m

λ = 4.538 × 10^-8 m

λ ≅ 454 Å

The wavelength (Å) of a photon that has an energy of 4.38 x 10-18 J is

(1) 454 Å

#SPJ2

Answer 2

The wavelength of a photon is 454 Å.

Given,

Energy = 4.38×$10^{-18}$ J.

To find:

The wavelength of a photon of the given energy.

Solution:

As we know the energy of the system is given by,

E=hυ

where h = Planck's constant and υ = frequency of light.

As υ= c/λ

According to the question, E= 4.38×$10^{-18}$ J

c= 3 ×$10^{8}$

h = 6.626×$10^{-34}$

Therefore, λ= 6.626×$10^{-34}$× 3 ×$10^{8}$/4.38×$10^{-18}$

=>λ= 4.538×$10^{-8}$ m

=>λ=454 Å.

Therefore, the wavelength (λ) is 454 Å.