Chemistry, asked by ohood9091, 7 months ago

What is the wavelength and frequency of electromagnetic radiation
having an energy of I rydberg (a rydberg is equal to 109 680 cm-1). Convert l
rydberg to electron volts and to kilojoules/mole (kJ ·mol-1).

Answers

Answered by arpitgodzilla990
1

Answer:

The idea here is to use Rydberg's equation to find the wavelength of the emitted electromagnetic radiation first, then convert this wavelength to energy using the Einstein-Planck equation.

So, the Rydberg equation looks like this

1

λ

=

R

(

1

n

2

1

1

n

2

2

)

, where

λ

- the wavelength of the emitted photon;

R

- the Rydberg constant, equal to

1.097

10

2

nm

1

;

n

1

- the principal quantum number of the orbital from which the transition is taking place;

n

2

- the principal quantum number of the orbital to which the transition is taking place.

Now, the first ionization energy is the energy needed to completely remove one mole of electrons from one mole of atoms in the gaseous state.

Since you didn't specify if you're looking for ionization energy per mole, I'll show you the value you'd have per atom.

So, completely removing an electron from an atom is equivalent to having

n

2

=

+

.

Removing an electron from

n

1

=

1

to

n

2

=

+

will require electromagnetic radiation of the wavelength

1

λ

=

R

(

1

1

2

1

)

=

R

(

1

0

)

=

R

This means that you have

λ

=

1

R

=

1

1.097

10

2

nm

1

=

91.16 nm

The Einstein-Planck equation, which establishes a relationship between photon energy and its frequency, looks like this

E

=

h

f

, where

R

- the energy of the photon;

h

- Planck's constant, equal to

6.626

10

34

J s

;

f

- the frequency of the photon.

SInce frequency and wavelength have the following relationship

c

=

λ

f

, where

c

- the speed of light in vaccuum,

3.0

10

8

ms

1

it follows that you can write

E

=

h

c

λ

Before doing any calculation, convert the wavelength from nanometers to meters

91.16

nm

1 m

10

9

nm

=

9.116

10

8

m

This means that you have

E

=

6.626

10

34

J

s

3.0

10

8

m

s

1

9.116

10

8

m

=

2.181

10

18

J

Expressed in kilojoules, this is equaivalent to

2.181

10

18

J

1 kJ

10

3

J

=

2.181

10

21

kJ

This means that if you supply this much energy to a hydrogen atom in its ground state, you will remove its electron completely.

SIDE NOTE To get the value in kJ per mole, the way it's usually reported, you need to first convert Joules to kilojoules, then use Avogadro's number.

2.181

10

21

kJ

atom

6.022

10

23

atoms

mole

=

1313 kJ/mol

similar question only you have to follow q rule and formula

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