Question

What is the wavelength and frequency of photon emitted during a transiction from n=5 state to then n=2 state?

Answer 1

Here,.. this transition falls under balmer series.
n(initial)=5, n(final)=2
as, ∆E=RH(1/n(initial)²-1/n(final)²)
So, substituting the values....
∆E= 2.18*10^-18J (1/5²-1/2²) = 2.18*10^-18J(1/25-1/4) = -4.58*10^-19 J (it is the value of energy emitted)
For frequency,v=∆E/h
=> v= (4.58*10^-19 J) /(6.626*10^-34Js)
=>v= 6.91*10^14 Hz
For wavelength..
lambda= c/v = 434 *10^-9
= 434 nm
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