What is the wavelength for the electron accelerated by 10⁴/volts?
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Explanation:
Step I. Calculating of the velocity of electron <br> Energy (kinetic energy ) of electron
volts. <br>
<br>
<br> or
<br> or
<br> Step II. calculation of the wavelength of electron <br> According to de Broglie equation, <br>
.
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Energy (kinetic energy ) of electron,
E = 1 × 10⁴ eV
⇒ E =1 × 10⁴ × 1.6 × 10⁻¹⁹
⇒ E = 1.6 × 10⁻¹⁵ J
⇒ E = 1.6 × 10⁻¹⁵ kg m² s⁻²
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1/2 mv² = 1.6 × 10⁻¹⁵
⇒ 1/2 × 9.1 × 10⁻³¹ × v² = 1.6 × 10⁻¹⁵
⇒ v = 5.93 × 10⁷ ms⁻¹
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According to de Broglie equation,
λ = h/mv
⇒ λ = (6.626 × 10⁻³⁴)/(9.1 × 10⁻³¹)(5.93 × 10⁷)
⇒ λ = 1.22 × 10⁻¹¹ m
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∴ Wavelength (λ) = 1.22 × 10⁻¹¹ m
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