Question

What is the wavelength of a photon that has an energy of 4.38×10^18j?

Answer 1

Answer:

Explanation:

E = hc/wavelength

h = 6.626 ×10^−34 J.s

c = 3.0 x 10^8 m/s

4.38 x 10^-18 J = (6.626×10^−34 J.s) (3.0 x 10^8 m/s) / wavelength

wavelength = (6.626×10^−34 J.s) (3.0 x 10^8 m/s) / 4.38 x 10^-18 J

= 4.54 x 10^-8 m

Your answer must be in nm.

1 nm = 10^-9 m

4.54 x 10^-8 m = 4.54 x 10^-8 m (1 nm/10^-9 m) = 45.4 nm

Answer 2

Hii

you are welcome in my ans

since lamda = hc/energy

lamda = 6.62*10^-34*3*10^8 / 4.38*10^18

lamda = 45.4 *10^-9m

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hope it may helps you✊✌️