Question

what is the wavelength of an electron moving with a velocity of 2.0×107 ms-1?​

Answer 1

Explanation:

The wavelength of an electron is obtained from de-Broglie equation.

λ=mvh

    =9.11×10−31kg×2.05×107m/s6.626×10−34Js

    =3.55×10−11m

Answer 2

Hence, the wavelength of the electron moving with a velocity of 2.05 × 107 ms–1 is 3.548 × 10–11 m.