Question

What is the wavelength of an electron moving with a velocity of 2.0 × 10⁷ ms⁻¹?

Answer 1

lambda=h/MV
=6.626*10-34/9.1*10^-31*2*10^7
=3.6*10^-10
=3.6 Angstroms

Answer 2

$\huge{\tt{\red{}\green{A}\purple{N}\pink{S}\blue{W}\orange{E}\red{R}}}☘$

✷⁠ Mass of electron = $\sf{}9.1 \times 10 {}^{ - 31} Kg$

✷⁠ Velocity of electron= $\sf{}2.0 \times 10 {}^{7} ms {}^{ - 1}$

✷⁠ Plank's constant(h)=$\sf{}6.625 \times 10 {}^{ - 34} J.sec$

✷⁠ Wavelength ($\lambda$)=$\sf{} \implies \frac{h}{mv} \\ \sf{} \implies \frac{6.625 \times 10 {}^{- 34} }{9.1 \times 10 { }^{ - 31 } \times 2.0 \times 10 {}^{7} } \\ \sf{} \implies3.64 \times 10 { }^{ - 11} m \\ \sf{} \implies0.364 A⁰$