Question

What is the wavelength of Dibrugli if an electron transmits a voltage difference of 300 volts?​. please help me

Answer 1

Answer:

The de Broglie wavelength an electron transmits a voltage difference of 300 volts is $7*10^{-11}m$

Explanation:

The de Broglie hypothesis is when a particle is moving with a velocity sometimes it acts like a particle or a wave, the wavelength of such a particle is given by the formula

λ=$h/p$

where $h=6.626*10^{-34} Js$ the Planck's constant and $p$ is the momentum of the particle.

for a charged particle the de Broglie wavelength is

λ$=h/\sqrt{2mqV}$

where $m$-the mass of the particle

$q$-charge of the particle

$V$-potential difference

here particle is electron so $m=9.1*10^{-31} kg, q=1.6*10^{-19} C,V=300volts$

substitute these values to get the wavelength of an electron

λ$=\frac{6.626*10^{-34} }{\sqrt{2*9.1*10^{-31}*1.6*10^{-19}*300 } }$

   =$7*10^{-11}m$