Question

What is the Wavelength of light emitted when the electronic in a Hydrogen atom undergoes translation from an energy level with n = 4 to energy level with n =2 ?

________________________

Sperms id will be Reported.​​

Answer 1

Answer :-

According to the formula,

$› \: Wave \: number, ν \: = R_{\text{H}}( \frac{1}{ {n_{\text{1}}}^{2}} - \frac{1}{ {n_{\text{2}}}^{2}})$

$› \: n_{\text{1}} = 2, \: n_{\text{2}} = 4 , \: R_{\text{H}} = 109678$

$› \: ν \: = 109678 \: ( \frac{1}{ {2}^{2} } - \frac{1}{ {4}^{2}})$

$› \: λ = \frac{1}{ν}$

$› \: λ = \frac{16}{109678} \times 3$

$› \: λ = 486 \: nm$

Hope it helps!