what is the wavelength of the electron if it has kinetic energy 4.55×10^-18J
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KE=21mv2=4.55×10−25
or 21×9.1×10−31×v2=4.55×10−25
or v2=9.1×10−312×4.55×10−25
v=103ms−1
Applying de Broglie equation,
λ=mvh=9.1×10−31×1036.6×10−34=0.72×10−6m.
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