Question

What is the wavelength of the second line (β-line or line with the second longest wavelength) in the Lyman series
of the hydrogen atom?

Answer 1

Answer:-

If an electron goes from $\sf{n_1 - n_2}$ in 2nd Lyman series, the value of $\sf{n_1}$ is 1 and $\sf{n_2}$ is 3.

We know that,

$\sf{\frac{1}{ \lambda} = R_{H} l{ \frac{1}{ n_2^2 } - \frac{1}{ n_1^2 }l}}$

Where ,

$\sf{\lambda\: is \: the\: wavelength\: of \: the \: electron\: and\: R_H\: is \:the \:Rydberg's\: Constant.\\\:The\:Value\:of\:R_H\:is\:1.09*10^7m}$

[Refer the attachment for wavelength]

Additional Information:-

Lyman series:

• It is a first series of spectral series of H.
• It was found out by Lyman in Ultraviolet region (U.V region) in 1898.
• It's value of $\sf{n_1=1}$ and $\sf{n_2 = 2 , 3 , 4}$ where n(1) is called ground state and n(2) is called excited state of electron present in a Hydrogen atom.