what is the wavelength of transition corresponding to last line of brackett series in he+ ion?
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Answer:
λ=4/R
Explanation:
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For the last line, the transition
n1= 4
n2= infinite
Z=2 ( for he+ ion)
Applying the formula,
1/λ = R(1/n₁²-1/n₂²)Z²
1/λ=R(1/4²-1/∞²)2²
1/λ=R/4
λ=4/R
The wavelength for the last line of transition of Brackett series in He+ ion,
is 4/R.
The Rydberg formula calculates it.
This formula is only valid for hydrogen-like ions.
Here, the n is a positive number, and Z indicates the atomic number of the element.
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