Question

what is the weight cubicle ice block 50 cm in the length if one cubic metre of ice weight is 900 kg ​

Answer 1

$\underline{\mathfrak{\huge{Question:}}}$

What is the weight of a cubical ice box of 50 cm in length ? Given the condition that one cubic metre ( 1 $m^{3}$ ) of ice weights 900 kg.

$\underline{\mathfrak{\huge{Answer:}}}$

Volume of a cube = $side^{3}$

Therefore, the volume of the cubical ice box with side 50 cm will be = $50^{3} cm^{3}$

=》 The volume will be = $125000 cm^{3}$

Convert the $cm^{3}$ into $m^{3}$ by dividing the value by 1000000 :-

Doing the same, we get :-

$\frac{125000}{1000000}$ = 0.125 $m^{3}$

Given to us is that :-

$\tt{1 m^{3} = 900\:kg}$

Then, according to the given condition :-

0.125 $m^{3}$ will be = 0.125 × 900

Multiplying it accordingly, we get the result to be as :-

=》 $\boxed{\tt{112.5 kg}}$

There's your answer !

Answer 2

What is the weight of cubicle ice block of 50 cm in the length, if one cubic metre of ice weight is 900 kg ?

Step by step explanation :

We know that,

$\tt{Volume\: of \:cube = (Side)^3}$

Thus,

$\tt{50{}^{3} = 50 \times 50 \times 50}$

$\tt{= 125000\:cm{}^{3}}$

Now, Let's convert this value into m^3 because according to your question, one cubic "metre" of ice weight is 900 kg.

So,

1 m^3 = 10,00,000 cm^3

$\tt{ \therefore \frac{125000}{10000000}} = 0.125 \: m{}^{3}$

Now,

Given that 1m^3 = 900 kg,

0.125m^3 = 900 × 0.125

Thus, Multiplying this, we get :

= 112.5 kg.

So, The weight of the cubicle ice block is 112.5 kg.