Question

what is the weight of 36.132×10^23 atoms of sulphur​

Answer 1

Atom is given which is 36.132 × 10²³

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= > We have to find weight of given atom :-

$We \: know \: that \: the \: formula :- \\ \\ \frac{Given \: mass}{Molar \: mass} = \frac{No \: of \: atom}{Avogadro \: number} \\ \\ We \: know \: use \: \: that \: formula \: here \: \ : - \\ \\ \frac{ Mass}{22} = \frac{36.132 \times {10}^{23} }{6.022 \times {10}^{23} } \\ \\ \frac{ Mass}{22} = \frac{\cancel {36.132 \times {10}^{23} }}{ \cancel {6.022 \times {10}^{23} }} \\ \\ \frac{ Mass}{22} = 6 \\ \\ Mass = 6 \times 22 \\ \\ Mass = 132 \: gram$

• Therefore, the mass is 132 gram in 36.132 × 10²³ atoms of Sulphur.

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Answer 2

Answer:1 gram atom = N – atoms = 6.023 x 1023 atoms = gram atomic weightgram atomic weight = weight of N atoms in grams1 gram molecule = N- ...