Question

What is the weight of 5 lit marcuary ? when dencity of marcury is 13.6 gm/cc

Answer 1

Answer:

Here is your answer.

M=?

v=5l=0.005 m3

d=13.6 g/cm3=13.6 ×1000 kg/m3

d=m÷v

m=d×v=13.6×1000 kg/m3 × 0.005 m3

=28 kg

or

= 5l

V 1l = 1000 cm^{3}

5l = 5×1000

= 5000 cm^{3}

D = 13.6g/cm^{3}

M = V×D

= 5000×13.6

= 68000 g

1000g = 1kg

1g = \frac{1}{1000}

∴ 68000g = \frac{1}{1000} * 68000

= 68 kg

or

The mass of 5 lit.

For 1 cm³ of Mercury will be 13.6 gram. = 68 kilogram.