Question

What is the weight of Ca present in Ca(NO3)2 that contains 1.4gm of nitrogen?​

Answer 1

Answer:

Explanation:

One molecule of Ca(NO3)2 contains 2 atoms of N.

Mass of nitrogen in one mole Ca(NO3)2 molecule = 28 g ( 2 x molar mass of nitrogen)

28g N = one mole molecule of Ca(NO3)2.

20 g N = 1x 20 /28 = 0.71 mole of Ca(NO3)2.

One molecule of Ca(NO3)2 contains 2 atoms of N.

1 mole Ca(NO3)2 = 40 g Ca

0.71 mole Ca(NO3)2 = 40 x 0.71 = 28.4 g Ca.

Answer 2

Answer:2.0gm

Explanation:

One molecule of Ca(No3)2 contains 2atoms of N.

Mass of nitrogen in one mole Ca(No3)2 molecules =28g.

28g N=1 mole of ca(no3)2.

1.4g N = 1.4÷28= 0.05 mole of Ca(No3)2.

One molecule of Ca(No3)2 contains 2 atoms of N.

1 mole Ca(No3)2 = 40g ca

0.05 mole Ca(No3)2=40×0.05÷100 = 2g. Ans.