Question

What is the weight of glucose added ​

Answer 1

s the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute. Now put all the given values in this formula ,we get the vapor pressure of the solution. Therefore, the weight of glucose that would have to be be added to 1700g of water is 1 gram.

Answer 2

Answer:

Explanation:

Depression in freeing point = m . Kf

let ‘x’ g of glucose is added in 1 L of water (1kg of water as density is 1g/cc for water )

mol. wt of glucose = 180 and moles

= wt / mol wt.

∆Tf =Kf × M

So, M = ∆Tf/Kf = 1/1000

M = moles of solute / volume of solution in litre

Volume of solution = 1litre

So, moles of glucose = 1/1000 = 0.001

Molar mass of glucose = 180 g

Mass of glucose required = 180 × 0.001

= 0.18 g

So, the correct option is option D. 0.18g

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