Question

What is the weight of H2SO4 in gram required to prepare 100 ml solution which can produce 1.2 * 10^22 H+ ions?

Answer 1

we have to find the weight of H₂SO₄ in gram required to prepare 100 ml solution which can produce 1.2 × 10²² H⁺ ions.

solution : no of moles of H⁺ ions = no of ions/avogadro's no

                                                      = (1.2 × 10²²)/(6.023 × 10²³) = 0.02 mol

dissociation reaction of H₂SO₄ is .. H₂SO₄ ⇄ 2H⁺ + SO₄²⁻

it is clearly shown that one moles of sulphuric acid dissociates into two moles of hydronium ions  and one mole of sulphate ions.

so, no of moles of sulphuric acid = no of moles of hydronium ions/2

                                                        = 0.02/2 = 0.01 mol

now the weight of sulphuric acid = no of moles of sulphuric acid × molecular weight of sulphuric acid

                        = 0.01 mol × 98 g/mol = 0.98g

therefore 0.98g required to prepare 100ml solution which can produce 1.2 × 10²² H⁺ ions.