What is the weight of NaOH present in 20cc of a 2 molar solution?
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Answer:
Explanation:
If pH =13, the pOH =14−13=1
If pOH =1,[OH
−
]=10
−
pOH =0.10
Since NaOH=0.10M,then:
0.10mol/L×0.250L=0.025molNaOH
Mass of NaOH=0.025mol×40g/mol=1gNaOH
If pH =13, the pOH =14−13=1
If pOH =1,[OH
−
]=10
−
pOH =0.10
Since NaOH=0.10M,then:
0.10mol/L×0.250L=0.025molNaOH
Mass of NaOH=0.025mol×40g/mol=1gNaOH
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