What is the weight of oxygen required for complete combustion of 2.4 kgs of ethylene
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Explanation:
The chemical equation for the said reaction is,
C2H4+12×2+4=283O296→2CO2+2H2O
the gram molar weight of ethylene is= 12*2+1*4 g
=28g
the gram molar weight of oxygen = 3*32 g
=96 g
∵ The weight of oxygen required for complete combustion of 28 g ethylene =96 g
according to question,
∴ Weight of oxygen required for combustion of 2.8 kg ethylene =96×2.8×100028×1000kg
=9.6kg
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