Question

What is the weight of oxygen required for complete combustion of 2.4 kgs of ethylene​

Answer 1

Explanation:

The chemical equation for the said reaction is,

C2H4+12×2+4=283O296→2CO2+2H2O

the gram molar weight of ethylene is= 12*2+1*4 g

=28g

the gram molar weight of oxygen = 3*32 g

=96 g

∵ The weight of oxygen required for complete combustion of 28 g ethylene =96 g

according to question,

∴ Weight of oxygen required for combustion of 2.8 kg ethylene =96×2.8×100028×1000kg

=9.6kg