Physics, asked by shellykhangembam, 5 months ago

what is the weight of oxygen required for complete combustion of 2.8 kg of ethylene​

Answers

Answered by itzcottoncandy65
2

The chemical equation for the said reaction is,

C2H4+12×2+4=283O296→2CO2+2H2O

the gram molar weight of ethylene is= 12*2+1*4 g  = 28g

the gram molar weight of oxygen = 3 * 32 g= 96 g  

∵ The weight of oxygen required for complete combustion of 28 g ethylene =96 g  

according to question,

∴ Weight of oxygen required for combustion of 2.8 kg ethylene    =96×2.8×100028×1000kg

=9.6kg

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