what is the weight of oxygen required for the complete combustion of 2.8kg of ethyle
Answers
Answered by
8
C2H4(ethylene) + 3O2 ———› 2CO2 + 2H2O
★Gram atomic mass of ethylene(C2H4) =(2×12+4×1)gm =(24+4)gm =28gm
★Gram atomic mass of oxygen (O2) = (2×16)gm = 32gm
★For oxydising 1mol of ethylene we require 3mol of Oxygen
★∴ For oxydising 28gm of ethylene we require (3×32)gm of oxygen
∴For oxidising 2.8kg of ethylene we require 9.6kg of oxygen
★Gram atomic mass of ethylene(C2H4) =(2×12+4×1)gm =(24+4)gm =28gm
★Gram atomic mass of oxygen (O2) = (2×16)gm = 32gm
★For oxydising 1mol of ethylene we require 3mol of Oxygen
★∴ For oxydising 28gm of ethylene we require (3×32)gm of oxygen
∴For oxidising 2.8kg of ethylene we require 9.6kg of oxygen
Similar questions