what is the weight of sucrose present in 1kg solution of 1m concentration?
please answer my que
the answer is 254.8gram
but i don't know how to solve it..
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Answer:
1m concentration means:
1 mole sucrose is present in =1000 g of solution
(wt of sucrose is=342.3 gram/mole)
i.e,342.3 g sucrose is present in = 1000g of solvent
342.3 g sucrose is present in = 1342.3g solution
(since, solution = solute + solvent)
so,1342.3g solution is present in =342.3g sucrose
so, 1000g solution is present in =((342.3)*1000)/1342.3
=254.8 g
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