Math, asked by tamangbrainlylang, 4 months ago

what is the width of a rectangle if the area is 6x^2-x-2 and has a length of 3x-2

Answers

Answered by himanshu88887

Answer:

The area of a rectangle is equal to the length times the width. So, the length is equal to the area divided by the width.

Your answer is (6x^2 + 5x - 6) / (3x - 2)

The key to solving this is to recognize that 6x^2 + 5x - 6 = (3x - 2) * (2x + 3). This is called factoring a quadratic equation. Factoring is the hardest thing you will do in grade 9 algebra. It takes practice.

The fact that the width is expressed as 3x - 2 is a hint that this will be part of the factoring of 6x^2 + 5x - 6. So think about what times (3x - 2) would equal the formula for the area.

Step-by-step explanation:

hope it's help you

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