Question

What is the work done by 0.2 mole of a gas at room temperature to double its volume during isobaric process?
(Take R = 2 cal mol^-1 °C^-1)

(1) 30 cal
(2) 40 cal
(3) 120 cal
(4) 160 cal​

Answer 1

Answer:

Work done 

  W=P(Vf−Vi)

=P(2V−V)

=PV

PVSo, we know that the work done 

W=PV=nRT

W=PV=nRTW=0.2×2×300

=120 cal

=120 calWhere n is the mole of gas, T is the temprature,