What is the work done by a centripetal force in quarter revolution
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Work done = integral of Force ยท ds ,over the arc.
Force F and ds (part of arc) are vectors. It is a dot product. Over a circular path F and ds are always perpendicular.
So dot product is 0.
So work done is 0.
Force F and ds (part of arc) are vectors. It is a dot product. Over a circular path F and ds are always perpendicular.
So dot product is 0.
So work done is 0.
kvnmurty:
Hope it's good
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