What is the work done by a motor to lift 500 kg of a block to 10 m height?
(a) 9800 J (c) 4900 J (b) 49000 J (d) 98000 J
Answers
Answered by
22
Answer:
Given :-
- A motor is lifted 500 kg of a block to 10 m height.
To Find :-
- What is the work done by a motor.
Formula Used :-
✪ Work Done = mgh ✪
where,
- m = Mass
- g = Acceleration due to gravity
- h = Height
Solution :-
Given :
- Mass = 500 kg
- Acceleration due to gravity = 9.8 m/s²
- Height = 10 m
According to the question by using the formula we get,
➦ Work Done = 500 × 9.8 × 10
➦ Work Done = 4900 × 10
➠ Work Done = 49000 J
∴ The work done by a motor is 49000 J .
Hence, the correct options is option no (b) 49000 J .
Answered by
9
Answer:
- (b) 49000 J
Explanation:
Given,
- Mass of Block, m = 500kg
- The Height, h = 10m
- Acceleration due to gravity, g = 9.8m/s²
To Find,
- The work done.
Solution,
The Work Done = mgh
- → The Work Done = 500kg × 9.8m/s² × 10m
- → The Work Done = 4900 × 10 kg m²/s²
- → The Work Done = 49000 kg m²/s²
- → The Work Done = 49000 J
Therefore,
- The work done by motor is 49000 J.
Required Answer,
- (b) 49000 J
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