Question

what is the work done by Nishad of his speed changes from 5km/hr to 10km/hr?Nishad's mass is 35kg....​

Answer 1

Answer:

Step-by-step explanation:

M=35kg,

U=5km/h = 25/18m/s

V=10km/h = 50/18m/s

Work done=change in K. E

K.E=1/2mv^2

=1/2×35×(50/18)^2

=1/2×35×2500/324

=87500/648

= 135.03J

K.E=1/2mv^2

=1/2×35×(25/18)^2

=1/2×35×625/324

=21875/648

=33.75J

135-33=102J

Hence work done= 102J

Answer 2

Answer:

102 Joules

Step-by-step explanation:

GIVEN :

• M=35kg,
• U=5km/h = 25/18m/s
• V=10km/h = 50/18m/s

We know that,

Work done (w)=change in Kinetic Energy  (K.E.)

So,

Initial K.E=1/2mu^2

              =1/2×35×(50/18)^2

              =1/2×35×2500/324

              =87500/648

              = 135.03J

Final K.E=1/2mv^2

             =1/2×35×(25/18)^2

             =1/2×35×625/324

             =21875/648

            =33.75 J

Now, work done :

Initial K.E. - Final K.E.

  135         -      33         =102J

So, the work done by Nishad on bicycle= 102J