Question

what is the work done for this figure
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Answer 1

Explanation:

here X =t^3/3

therefore differentiate it therefore X= t^2

again differentiate to find acceleration

therefore X= 2t

we know work done = force × displacement

we know force = mass × acceleration= 1kg × 2t

therefore 1 kg × 2t × t^3/3 =

at time = 1 second

1×2×1/3= 2/3joules