what is the work done in blowing a soap bubble of radius r and surface tension s?
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Answered by
116
We know that a bubble has two surfaces in contact with air, so the total surface area of the bubble will be
=2×(4πR2)=8πR2Now, work done=Surface tension × Increase in surface area=T×(8πR2−0)=8πR2T
=2×(4πR2)=8πR2Now, work done=Surface tension × Increase in surface area=T×(8πR2−0)=8πR2T
Answered by
51
Answer:
8πr²T
Explanation:
Radius of soap bubble = r (Given)
Surface tension of soap bubble = s (Given)
Work = Force × Displacement OR
Work = Surface tension × Change in the surface area
The bubble always has two surfaces- the outer surface and the inner surface, thus the total surface area of bubble will be -
= 2 × 4πr²
= 8πr²
Since work done = Surface Tension × Increase in the surface area
= T × ( 8πr² - 0 )
= 8πr²T
Therefore, the work done in blowing a soap bubble of radius r and surface tension is 8πr²T.
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