Question

What is the work done in placing three identical particles each of mass m at the vertices of an equilateral triangle of side ?​

Answer 1

Answer:

please mark me brainalist

Explanation:

We know that the gravitational field to conservative.

W=−(△PE)

system

△PE=(PE

final

−PE

Initial

Since initially the particles A,B and C were at infinity, their initial gravitational potential energy was zero

⇒△PE=PE

final

The gravitational potential energy of the configuration of the particles =PE between A and B+PE between B and C+PE between C and A

⇒△PE=

Gm

A

m

B

)+(−

l

Gm

B

m

c

)+(−

l

Gm

C

m

A

Putting m

A

=m

B

=m

C

=m, we obtaine,

△PE=

l

3Gm

2

Using (1) and (2), we obtain, W=3 Gm

2