Physics, asked by jadhavsandhya822, 4 months ago

What is the work done is pulling a body of mass 80kg through 100m if the cofficient of friction is 0.7 and g=10ms-2​

Answers

Answered by srishti539
1

Answer:

From the Question,

Mass of the block,m = 80 Kg

Displacement,s = 100 m

Coefficient of Friction,u = 0.7

To find

Work Done by the frictional force.

Firstly,we need to find the fictional force

\huge{\boxed{\boxed{\sf{f = \mu mg}}}}

f=μmg

Substituting the values,we get :

→ f = (0.7)(80)(10)

→ f = (7)(80)

→ f = 560 N

Now,

\huge{\boxed{\boxed{\tt{W = f.s}}}}

W=f.s

→ W = (560)(100)

→ W = 56,000

→ W = 56 KJ

Thus,the work done by the frictional force is 56 KJ

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