What is the work done is pulling a body of mass 80kg through 100m if the cofficient of friction is 0.7 and g=10ms-2
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Answer:
From the Question,
Mass of the block,m = 80 Kg
Displacement,s = 100 m
Coefficient of Friction,u = 0.7
To find
Work Done by the frictional force.
Firstly,we need to find the fictional force
\huge{\boxed{\boxed{\sf{f = \mu mg}}}}
f=μmg
Substituting the values,we get :
→ f = (0.7)(80)(10)
→ f = (7)(80)
→ f = 560 N
Now,
\huge{\boxed{\boxed{\tt{W = f.s}}}}
W=f.s
→ W = (560)(100)
→ W = 56,000
→ W = 56 KJ
Thus,the work done by the frictional force is 56 KJ
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