what is the work done needed to stop a car of 1500 kg moving at a velocity of 60km/h
Answers
Answered by
2
Work Done = Change in K.E
Initial K.E= 1/2 m(u)2
= 1/2 1500×(16.7)square
= 209250 J
Final K.E= 0J
Work done= 0-209250
= -209250 J
So, work done by retarding force is 209250 J.
Initial K.E= 1/2 m(u)2
= 1/2 1500×(16.7)square
= 209250 J
Final K.E= 0J
Work done= 0-209250
= -209250 J
So, work done by retarding force is 209250 J.
Answered by
1
Hey there!
Given,
Mass of car (m) = 1500 kg
Velocity of car ( v) = 60 km/h = 60 * 5/18 m/s
Work done = ?
Here,
Work done = Kinetic Energy
= 1/2 * mv²
= 1/2 * 1500 * 60 * (5/18) J
= 20.8 × 10⁴ J (←Answer)
Hope It Helps You!
Similar questions