. What is the work done to increase the velocity of a car from 36 km/h to 72 km/h, if mass of ca is 1500 kg?
Answers
Given,
Initial velocity 'u' = 36 km/h
Final velocity 'v' = 72 km/h
Mass of car 'm' = 1500 Kg.
To find,
Work done to increase the velocity of a car from 36 km/h to 72 km/h if the mass of the car is 1500 kg.
Solution,
We can simply solve the above numerical by using the concept that
Work done to increase the velocity = change in kinetic Energy
Initial velocity 'u' = 36 km/h
= 36*1000/1800
= 10 m/s
Final velocity 'v' = 72 km/h
= 72*1000/1800
= 20 m/s
Work done = change in kinetic energy
= 1/2 m(v²-u²)
= 1/2*1500*(400-100)
= 225000 Joule
Hence, the work done to increase the velocity of a car from 36 km/h to 72 km/h, if the mass of the car is 1500 kg is 225000 Joule.
Concept:
Work done to increase the velocity can be defined as the change in kinetic energy.
Given:
Initial velocity of car, u = 36 km/h = 10 m/s
Final velocity of the car, v = 72 km/h = 20 m/s
Mass of car, m = 1500 kg
Find:
Work done required to do to increase the velocity of a car from 36 km/h to 72 km/h when the mass of the car is 1500 kg.
Solution:
As Work done = change in kinetic energy
W = 1/2 m(v²-u²)
W = 1/2 × 1500×(400-100)
W = 225000 J = 225 kJ
Hence, the work done required to increase the velocity of a car from 36 km/h to 72 km/h when the mass of the car is 1500 kg is 225 kilojoules.
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