Question

What is the work done when 1 mole of a gas expands
isothermally from 25 L to 250 L at a constant pressure
of 1 atm and a temperature of 300 K?
(a) - 3542 J
(b) - 5744 J
(c) - 2657 J
(d) - 4890 J
-​

Answer 1

Answer:

Work done (W)=−nRTln(

V

1

V

2

)=−1×8.314×300×ln(

25

250

)

∴ Work done(W)=−5744J