What is the work function of a metal if the threshold wavelength for it is 580 nm? If light of 475 nm wavelength falls on the metal, what is its stopping potential?
Answers
Answered by
5
Given:
Threshold wavelength = 580nm
Wavelenght of light = 475nm
To Find:
The stopping potential
Solution:
Work function = hc/λ0
(6.626 x 10`34) ( 3 x 10`8)/ ( 580 x 10`9) (1.6 x 10`19)
= 2.14 ev
Energy of 475nm radiation = hc/ λ
= (6.626 x 10`34) ( 3 x 10`8)/ ( 475 x 10`9) (1.6 x 10`19)
= 2.62 ev
Stopping Potential
= 2.62 - 2.14
= 0.48V
Answer: The stopping potential is 0.48V.
Answered by
2
Answer:
Work function = hc/λ0
(6.626 x 10`34) ( 3 x 10`8)/ ( 580 x 10`9) (1.6 x 10`19)
= 2.14 ev
Energy of 475nm radiation = hc/ λ
= (6.626 x 10`34) ( 3 x 10`8)/ ( 475 x 10`9) (1.6 x 10`19) = 2.62 ev
Stopping Potential
= 2.62 - 2.14 = 0.48V
The stopping potential is 0.48V.
Hope it helps you...
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