Physics, asked by Anjalikundu, 11 months ago

What is the work function (wo) of the metal whose threshold frequency (v) is 5.2 x 1014 5-1?


Answers

Answered by abhi178
16

What is the work function (wo) of the metal whose threshold frequency (v) is 5.2 x 1014 5-1?

solution : Work function of a metal is the amount of energy required to remove an electron from metal surface.

according to Plank's theory,

  • work function = plank's constant × threshold frequency

given, Threshold frequency = 5.2 × 10¹⁴ Hz

we know, plank's constant = 6.63 × 10^-34 J.s

so, work function = 6.63 × 10^-34 × 5.2 × 10¹⁴ = 34.476 × 10^-20 J

= 3.4476 × 10^-19 J

hence, work function orThreshold energy of the metal is 3.4476 × 10^-19 J

Answered by Aditya27kumar78
5

Answer:

Explanation:threshold Freq..=5.2*10¹⁴

W•=h*threshold Freq..

W•=6.23*10^-34*5.2*10¹⁴

W•=3.276*10^-19

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