What is the work function (wo) of the metal whose threshold frequency (v) is 5.2 x 1014 5-1?
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What is the work function (wo) of the metal whose threshold frequency (v) is 5.2 x 1014 5-1?
solution : Work function of a metal is the amount of energy required to remove an electron from metal surface.
according to Plank's theory,
- work function = plank's constant × threshold frequency
given, Threshold frequency = 5.2 × 10¹⁴ Hz
we know, plank's constant = 6.63 × 10^-34 J.s
so, work function = 6.63 × 10^-34 × 5.2 × 10¹⁴ = 34.476 × 10^-20 J
= 3.4476 × 10^-19 J
hence, work function orThreshold energy of the metal is 3.4476 × 10^-19 J
Answered by
5
Answer:
Explanation:threshold Freq..=5.2*10¹⁴
W•=h*threshold Freq..
W•=6.23*10^-34*5.2*10¹⁴
W•=3.276*10^-19
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