Question

What is the work needed to be done to increase the velocity of a car from 30
Kmh to 60 Kmh-1 if the mass of the car is 1500 kg
The sum of the kinetic and potential energies of an object is called its​

Answer 1

Answer:

Answer:ANSWER

Answer:ANSWERInitial velocity u=30 km/h=30×

Answer:ANSWERInitial velocity u=30 km/h=30× 18

Answer:ANSWERInitial velocity u=30 km/h=30× 185

Answer:ANSWERInitial velocity u=30 km/h=30× 185

Answer:ANSWERInitial velocity u=30 km/h=30× 185 =

Answer:ANSWERInitial velocity u=30 km/h=30× 185 = 3

Answer:ANSWERInitial velocity u=30 km/h=30× 185 = 325.

m/s

m/sFinal velocity v=60 km/h=60×

m/sFinal velocity v=60 km/h=60× 18

m/sFinal velocity v=60 km/h=60× 185

m/sFinal velocity v=60 km/h=60× 185

m/sFinal velocity v=60 km/h=60× 185 =

m/sFinal velocity v=60 km/h=60× 185 = 3

m/sFinal velocity v=60 km/h=60× 185 = 350

m/sFinal velocity v=60 km/h=60× 185 = 350

m/sFinal velocity v=60 km/h=60× 185 = 350 m/s

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kg

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W=

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 −

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W=

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )=

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×((

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 3

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350 )

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350 ) 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350 ) 2 −(

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350 ) 2 −( 3

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350 ) 2 −( 325

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350 ) 2 −( 325

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350 ) 2 −( 325 )

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350 ) 2 −( 325 ) 2

m/sFinal velocity v=60 km/h=60× 185 = 350 m/sMass m=1500 kgWork done W= 21 mv 2 − 21 mu 2 ⟹ W= 2m (v 2 −u 2 )= 21500 ×(( 350 ) 2 −( 325 ) 2 )=156187 J.

Answer 2

Answer:

Work done is 156250 J.

Explanation:

Given,

The mass (m) of the car is 1500 kg.

Initial velocity of car = u = 30 km / hr = 30 * 5/18 = 25 / 3 m/s

Final velocity of car = v = 60 km / hr = 60 * 5/18 = 50/3 m/s

To find: The work to be done to increase the velocity of a car from

30 km h-1 to 60 km h^-1

Solution:

Initial kinetic energy = Ki = 1/2mu² = 1/2*1500*25/3 * 25/3 = 156250/3 J

Final Kinetic energy = Kf = 1/2mv² = 1/2*1500*50/3*50/3 = 625000/3 J

Work done can be given as change in Kinetic Energy,

i.e W = ΔK.E

or, W = Kf -  Ki

or, W = 625000/3 - 156250/3

or, W = 156250 J

Therefore, Work done is 156250 J.

The sum of the kinetic and potential energies of an object is called its​ Mechanical Energy