What is the work to be done in increase the velocity of a car from 30 km h-¹ to 60 km h-¹ if the mass of the car is 1500 kg?
Answers
Answer:
156375 J.
Explanation:
Mass of the car , m = 1500 kg,
initial velocity of car , u = 30 km h-¹
30 × 1000 m
_____________
60 × 60 s
= 8.33 ms-¹.
Similarly , the final velocity of the car ,
v = 60 km h-¹
= 16.67 m s-¹
Therefore , the initial kinetic energy of the car ,
Eki = 1/2 mu²
= 1/2 ×1500 kg × (8.33 ms-¹)²
= 52041.68 J.
The final kinetic energy of the car ,
Ekf = 1/2 × 1500 kg × ( 16.67 m s-¹)²
= 208416.68 J.
Thus , the work done = Change in kinetic energy
= Ekf - Eki
156375 J.
Answer:
Explanation:
m=1500kg,
u=30kmh-¹
30×1000m
60×60s
=8.33ms-¹.
finalvelocityofthecar,
v=60kmh-¹
=16.67ms-¹
initialkineticenergyofthecar,
Eki =1/2mu²
=1/2×1500kg×(8.33ms-¹)²
=52041.68J.
=>>
Ekf =1/2×1500kg×(16.67ms-¹)²
=208416.68J.
Thus,theworkdone=Changeinkineticenergy
=Ekf -Eki
156375J.
Hope it will help you with