Question

What is the work to be done to increase the velocity of a car from 30 km h -¹ to 60 km h -¹if the mass of the car is 1500 kg?​

Answer 1

30km/h = 8.333m/s and 60km/h = 16.667m/s

The work done is the change in kinetic energy, which is

ΔEk = ½m(V1^2 – V0^2) = ½(1500)(16.667^2 – 8.333^2) = 156.262kJ.

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Answer 2

Answer:

Work done is 156250 J.

Explanation:

Given,

The mass (m) of the car is 1500 kg.

Initial velocity of car = u = 30 km / hr = 30 * 5/18 = 25 / 3 m/s

Final velocity of car = v = 60 km / hr = 60 * 5/18 = 50/3 m/s

To find: The work to be done to increase the velocity of a car from

30 km h-1 to 60 km h^-1

Solution:

Initial kinetic energy = Ki = 1/2mu² = 1/2*1500*25/3 * 25/3 = 156250/3 J

Final Kinetic energy = Kf = 1/2mv² = 1/2*1500*50/3*50/3 = 625000/3 J

Work done can be given as change in Kinetic Energy,

i.e W = ΔK.E

or, W = Kf -  Ki

or, W = 625000/3 - 156250/3

or, W = 156250 J

Therefore, Work done is 156250 J.