What is the work to be done to increase the velocity of an object of mass 1200kg
from 30 m/s to 60 m/s.
Answers
Answered by
1
Here in this case.....
Work done = change in kinetic energy
W = 1/2m ( v^2 - u^2)
Where v is final velocity
And u is initial velocity......
Therefore....
W = 1/2*1200 (3600- 900)
W = 162 *10^4
W = 1.62 MJ
Answered by
0
Answer:
30 m/'s +60 m/'s= 90 min × 60 seconds = 5400 second
Explanation:
mass=1200
velocity =speed/distance
work= 1200/5400 =
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