What is the work to be done to increase the velocity of car from 35km/h to 65km/h if the mass of car is 2000kg
Answers
Answered by
0
work done = Force x displacement
but force =mass x acceleration
work done W= mass x displacement ……(1)
using V^2=u^2+2as
or, (65000/60x60)^2=(35000/60x60)^2+2a (since si unit of velocity is m/sec.square and time is second)
as=(18.05)^2-(9.72)^2
as=(325.8025 -94.4784)
as=231.324
putting the value of as in equation 1
W=m(as)
W=2000x231.324 joules
W=462.648 joules
I HOPE THIS WILL HELP YOU...
but force =mass x acceleration
work done W= mass x displacement ……(1)
using V^2=u^2+2as
or, (65000/60x60)^2=(35000/60x60)^2+2a (since si unit of velocity is m/sec.square and time is second)
as=(18.05)^2-(9.72)^2
as=(325.8025 -94.4784)
as=231.324
putting the value of as in equation 1
W=m(as)
W=2000x231.324 joules
W=462.648 joules
I HOPE THIS WILL HELP YOU...
Answered by
4
In first case
mass = 2000 kg
velocity = 35 km/h = 35 * 5/18 = 9.72 m/s
kinetic energy = 1/2 m v^2
= 1/2 (2000)(9.72)^2
= 1/2 (2000)(94.9784)
= 94478.4 J
In second case
mass = 2000 kg
velocity = 65 km/h = 65 * 5/18 = 18.05 m/s
kinetic energy = 1/2 m v^2
= 1/2 (2000)(18.05)^2
= 325802.5 J
Work done = increase in kinetic energy
= ( 325802.5 - 94478.4 )
= 231324.1 J
Hope this answer help u
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