What is the work to be done to increase the velocity of car 30/kmp 60km/hour of the mass of if 1500 kg
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Answered by
1
W = F x s
W = m a x (v² - u² )/ 2a
W = m(v² - u² ) /2
W = 1500 ( 16.6 x 16.6 - 8.3 x 8.3 ) / 2
W = 1500 ( 275.56 - 68.89 ) / 2
W = 1500 x 188.67 / 2
W = 283005 / 2
W = 141502.5 Joules
W = 141.5 KJ
W = m a x (v² - u² )/ 2a
W = m(v² - u² ) /2
W = 1500 ( 16.6 x 16.6 - 8.3 x 8.3 ) / 2
W = 1500 ( 275.56 - 68.89 ) / 2
W = 1500 x 188.67 / 2
W = 283005 / 2
W = 141502.5 Joules
W = 141.5 KJ
Answered by
1
m=1500kg
u= 60km/h =60* 5/18 = 50/3m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 15000{0- (50/3)2}
= -208333.33J
u= 60km/h =60* 5/18 = 50/3m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 15000{0- (50/3)2}
= -208333.33J
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