what is the work to be done to increase the velocity of car from 30 kmph to 60 kmph if the mass of car is 15000
Answers
Answer:
Given :
mass: 15000
initial velocity: 30kmph
final velocity: 60kmph
work done = change in kinetic energy
K.E = 1/2m( v² - u²)
= 1/2 × 15000( 30² - 60² )
= 7500( 900- 3600)
=7500 × ( - 2700)
= - 20250000 J
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Answer:
initial velocity u=30*1000/3600
=30000/3600
=25/3 m/s
final velocity v=60*1000/3600
=60000/3600
=50/3 m/s
mass of the car m = 15000kg
According to work kinetic energy theorem
work done (w) = ∆ KE
w= 1/2 mv^2 -1/2mu^2
=1/2m (v^2-u^2)
=1/2*15000 [(50/3)^2 - (25/3)^2]
=7500 [ (50/3 +25/3) (50/3-25/3) ]
=7500 [(75/3) (25/3) ]
=7500(1875/9)
=7500(208.33)
=1,562,475J